# Question: 020 kg of air at pressure of 113 kpa occupies...

###### Question details

0.20 kg of air at pressure of 113 kPa occupies 0.18 m3 and from
this condition it is compressed to 1237 kPa accordingly to the law
P*(V)^{1.28} = constant. Determine change of internal
energy of the air in **kJ**,

Cp=1.005 kJ/kg K

Cv=0.718kJ/kg K

R=0.287 kJ/kg K