# Question: 1 the hypothetical velocity distribution in a horizontal rectangular openchannel...

###### Question details

1) The hypothetical velocity distribution in a horizontal,
rectangular, open-channel is *v* = 0.45*y* (m/s),
where *v* is the velocity at a distance *y* (m) above
the bottom of the channel. The vertical flow depth is 3.2 m and the
width of the channel is 15 m a) What is the maximum velocity? b)
What is the discharge? c) What is the mean velocity?