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Question: 47 enzyme kinetics iii five solutions of a substrate s...

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47) Enzyme kinetics III Five solutions of a substrate S were prepared with the concentration in the first column below, and each one was divided into three equal volumes. The same concentration of enzyme was present in each one. An inhibitor I was then added in different concentrations to the samples and the initial rate of formation of product was determined with the results given below (values in μmol L-1 s-1) lU]/mmol L-1 [S]/mmol L 0.00 0.40 0.80 0.05 0.10 0.20 0.40 0.60 0.033 0.021 0.016 0.055 0.038 0.029 0.083 0.062 0.050 0.111 0.091 0.077 0.126 0.108 0.094 i) Does the inhibitor act competitively or non-competitively? Please also argue how you come to this decision. ii) Determine Ki and KM.

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