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Question: 5 two tds equations tds du pdv and...

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5. Two Tds equations (Tds - du + pdv and Tds - dh - vdp) can be used to describe change of entropy a. Considering a phase change process from saturated liquid to saturated vapor of water at 60 °C, 1) derive the expression for the entropy change in a function of enthalpies and temperature. 2) Also calculate the entropy changes for the entire process from saturated liquid to saturated vapor, using the saturated water table below. Continued) Specific Vel Sat. 10 Internal Energy Eethalpy Entragy TempPressudVapor C bar 1235 10121 12.032 209.32 2443.5 209.33 2382.7 2592.17038 8.0763 50 .1576 10146 | 9.568 | 20.21 | 2450.1 | 230.23 | 2370.71 2600.91 .7679| 7.9013 ss 25111 2456.6 251.13 2358.5 2609.6 8312 7.9096 60 272.02 | 2441.1 | 272.06 | 2346.2 | 2618.3 丨 .8935 | 78310 | 65 60 65 70 7.671 25031.01996.197 1994 1.0172 .3119 | 1.0228 | s.042 | 292.95| 2469.6 | 292.98| 23าน| 2626.8 | 3549| 7.7553| 70 b. For incompressible substance (dv 0), 1) derive the expression for the entropy change with the initial and final temperatures (Ti and T2, respectively), by assuming constant specific heat (c). 2) Then, calculate the entropy change for a system consisting of liquid water initially at Tİ :-300 K, pi 2 bar undergoing a process to a final state at T.-350 K, p2 1 bar. Here, the constant specific heat is 4.2 kJ/kg K.
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