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  3. 642 561549 exit soiving the probiem 3 my total profit...

Question: 642 561549 exit soiving the probiem 3 my total profit...

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6:42 56:15:49 Exit soiving the probiem. 3. My total profit function, P(x), is a downfacing parabola with two roots. For what value(s) of x can I expect positive profits? Use the vertex formula: positive profits are only obtained for x--b/2a. Any value of x between the two roots will yield positive profits. All x values less than the smaller root and greater than the larger root will yield positive profits. Positive profits will occur at the two roots, these are the break even points. 4. Sliding price scales, where the price per item decreases as the number of items purchased increases, can be common in business. If my price function p(x) is linear
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6:42 v 56:15:54 Exit Sliding price scales, where the price per item decreases as the number of items purchased increases, can be common in business. If my price function p(x) is linear and decreasing, what will my total revenue function look like? Total revenue will be a decreasing linear function since the price is decreasing Total revenue will be an increasing linear function since the price is increasing Total revenue will be a downfacing parabola since R(x)-p(x)*x and p(x) has a negative slope Total revenue will be a upfacing parabola since R(x)-p(x)*x and p(x) has a positive slope 5. For a quadratictatalprofit faunction P(x),
6:42 0 56:15:58 Exit 5 For a quadratic total profit function P(x), how can I determine the maximum possible profit? Use the vertex formula to get x=-b/2a. The maximum possible profit is -b/2a. Use the quadratic formula. Plug all values of x found back into P(x) to get the maximum possible profits. Use the quadratic formula. If the values of x found are positive, these are the values of maximum possible profit Use the vertex formula to get x-b/2a, then plug that value into the profit function. The maximum possible profit is P(-b/2a). Submit
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