Question: a student did the reaction shown in the balanced equation...

A student did the reaction shown in the balanced equation below and 3.05 g of solid CuS (molar mass 95.61 g/mol) was obtained. In the experiment, 7.58 × 10–2 mol of CuSO4 was combined with excess Na2S (CuSO4 was the limiting reactant). What was the percentage yield of the reaction?

Na2S(aq) + CuSO4(aq) → Na2SO4(aq) + CuS(s)