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  3. answer is 178x105 kg if your solution does not give...

Question: answer is 178x105 kg if your solution does not give...

Question details

7.2. Ice condenser containment analysis (Section 7.2) Calculate the minimum mass of ice needed to keep the final containment pres- sure below 0.4 MPa, assuming that the total volume consists of a 5.05 x 104 m3 containment volume and a 500 m3 of the ice. Additionally, assume the following initial conditions: primary volume. Neglect the initial volume Containment pressure 1013 x 105 Pa (1 atm) Containment temperature 300K Ice temperature 263 K 10°C) Ice pressure 1.013 x 105 Pa (I atm) Primary pressure 15.5 MPa (saturated liquid conditions) Relevant properties are: c, for air 719 J/kg K R for air 286 J/kg K c for ice 4.23 x 103 J/kg K Heat of fusion for water 3.33x 10 J/kg (at 1 atm) Answer: 1.78 x 105 kg of ice

ANSWER IS 1.78x10^5 kg. IF YOUR SOLUTION DOES NOT GIVE THIS VALUE DO NOT BOTHER SUBMITTING.

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