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Question: could someone please assist me with this solid lead sulfide...

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Could someone please assist me with this?

 

Solid lead sulfide dissolves in a concentrated solution of nitric acid, forming aqueous lead nitrate and hydrogen sulfide gas.  The balanced equation for this reaction is …

PbS (s)   +   2 HNO3 (aq)   →   Pb(NO3)2 (aq)   +   H2S (g)

Consequently, if we have excess lead sulfide but only 0.5 mole of nitric acid, how many mole of lead nitrate we would expect to get?

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