Question: could someone please assist me with this solid lead sulfide...
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Could someone please assist me with this?
Solid lead sulfide dissolves in a concentrated solution of nitric acid, forming aqueous lead nitrate and hydrogen sulfide gas. The balanced equation for this reaction is …
PbS (s) + 2 HNO3 (aq) → Pb(NO3)2 (aq) + H2S (g)
Consequently, if we have excess lead sulfide but only 0.5 mole of nitric acid, how many mole of lead nitrate we would expect to get?
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