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Question: coulombs law for the magnitude of the force f between...

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Coulomb's law for the magnitude of the force F between two particles with charges Q and Q′ separated by a distance d is |F|=K|QQ′|d2, where K=14πϵ0, and ϵ0=8.854×10−12C2/(N⋅m2) is the permittivity of free space. Consider two point charges located on the x axis: one charge, q1 = -17.5 nC , is located at x1 = -1.740 m ; the second charge, q2 = 36.0 nC , is at the origin (x=0.0000).

A) What is the net force exerted by these two charges on a third charge q3 = 51.0 nC placed between q1 and q2 at x3 = -1.240 m ?

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