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Question: differential equations can someone explain what happened in the red...

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(Differential Equations)

Can someone explain what happened in the red box? I don't understand how substituting y^-3 = u into the equation became -3y^-4 dy/dx = du/dx

niYen MC Now, D.v.de both ç e d 4 du 3 dX the on )Becomes Now 3 dn Mu both sides on inoan he above diun on

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