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Engineering application program
. Fall in the blanks oe the right so both code fragments are logicaly idetical Left code fragment Right code fragne quot a dividend/divisor Ese Magd Ovision by 2ero is not alowed. End End It 2. Shown here is a function named sEven that roturms True if te iut Long valu is an even number. Otherwise the function returms False (when ode Function isEven kinput as Lon as Boolean Complete the function below by naming it sod. The function should neum True if the npu is edd, otherwise return False (when even) Then 3. Look at the code fragment and fill in the blank with the comroct ansower by llowig (tracing) the logic Dim x an Long x 11 ( xx11)Then MsgBoxl The inal value of -1
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