Question: five males with an xlinked genetic disorder have one child...
Question details
Five males with an Xlinked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the Xlinked genetic disorder. Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviation. If a probability distribution is not given, identify the requirements that are not satisfied. 
x 
P(x) 


0 
0.0330.033 

1 
0.1620.162 

2 
0.3050.305 

3 
0.3050.305 

4 
0.1620.162 

5 
0.0330.033 
Does the table show a probability distribution? Select all that apply.
A.
Yes, the table shows a probability distribution.
B.
No, not every probability is between 0 and 1 inclusive.
C.
No, the random variable x's number values are not associated with probabilities.
D.
No, the sum of all the probabilities is not equal to 1.
E.
No, the random variable x is categorical instead of numerical.
Find the mean of the random variable x. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A.
muμequals=nothing
child(ren) (Round to one decimal place as needed.)
B.
The table does not show a probability distribution.
Find the standard deviation of the random variable x. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A.
sigmaσequals=nothing
child(ren) (Round to one decimal place as needed.)
B.
The table does not show a probability distribution.