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Question: for any x is in zn and any k is...

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For any
[x] is in Z/n
and any
k is in Z,
we can define k[x] by

13. -17.72 points HunterDM3 2.4.030 My Notes For any xEz/n and any kez, we can define k[x] by k[x)[x) x)x] k times where the result is an element of Z/n. We say k[x] is a multiple of [x] (a) List all the multiples of [3] in Z/9. (Select all that apply.) O [o] O [2] O [3] O [4] O [5] o [6] o 17] o [8] (b) List all the multiples of [5] in z/8. (Select all that apply.) O [o] O [2] O [3] O [4] o [5] O [6] o [7]
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