# Question: i got 23lnx211tlnyc got c4233 for t1 i think im...

###### Question details

I got 2/3ln(x^2+1)=(1/t)ln(y)+c

got C=(4^2/3)/(3) for t=1

I think im doing it right I just need someone to confirm and show me how to do the graphs.

I got 2/3ln(x^2+1)=(1/t)ln(y)+c

got C=(4^2/3)/(3) for t=1

I think im doing it right I just need someone to confirm and show me how to do the graphs.