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Question: i have the answer for the first equation of answer...

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0.005(0.08) (0.01) 210.03(0.04) (0.01)] 0.08(0.01) + 2(0.04) (0.01) = 0.0175 m 10.08)(0.013) + 0.08(0.01)(0.01252) 12 + 2[ (0.01)(0.043) 0.01(0.04)(0.0125)) = 0.3633(10-6) m4 12 Mc 75(0.0175) Ans 1-0.3633(10%) = 3.61 MPa My-75(0.01 75-001) 1.55 MPa Ans 0.3633(10-6)20 mm 10 mm 20 mm 10 mm 10 mm 10 mm 10 mm M-75 N m 40 mm Figure 5: Aluminium machine part The aluminium machine part shown in Figure 5 is subjected to a moment M = 75 Nm. Given that the neutral axis is 0.0175 m from the top surface of the top flange, determine: (a) The second moment of area about the neutral axis. (b) The bending stress created at point B.

i have the answer, for the first equation of answer, where does 0.03 and 0.005 from, i dont think it is in the formula

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