Question: let cp represent the event that the ankle was truly...
Question details

Let CP represent the event that the ankle was truly fractured, and let T+ represent the event that the test said it was. From the table, estimate P(CPT+) (the positive predictive value and P(CAT) (the negative predictive value).
Predicted by the Ottawa Ankle Test Truth Regarding Fracture
Not Fractured  Fractured  Totals
Not Fractured  51  5  56
Fractured  277  88  365
Totals  328  93  421