1. Math
  2. Advanced Math
  3. please explain thanks...

Question: please explain thanks...

Question details

ur)exp (a)dr (15) and r(z) = / r(r) u (z) dz + C. (16) We see that the integrating factor, u(r). is in fact easily chosen to simplify the problem. It is just the exponential of the anti-derivative of q(x), and is a solution to the homogeneous equation. since any such solution will do, no integration constant is necessary at this stage. The solution to the original IFOLDE is thus y(z) =- (r) u(x) r(r) u() dr+ C (17) Exercise 13 Assure yourself through substitution that Eqn. 17 is a solution of Eqn. 9. 18Tutorial FODE: Ordinary First-Order Differential Equations first or zeroth powers in any term in the equation. The general form of a FOLDE is thus dy(r) + q(x) y(z) = r(x) ,

Please explain! thanks

Solution by an expert tutor
Blurred Solution
This question has been solved
Subscribe to see this solution