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  3. plz do number 4 number 2 answer is 418106 ev...

Question: plz do number 4 number 2 answer is 418106 ev...

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Plz do number 4, number 2 answer is 4.18*10^-6 ev
2. What should be the energy of an electron so that the associated electron waves have a wavelength of 600 nm? 3. Since the visible region spans between approximately 400 nm and 700 nm why can the electron wave mentioned in Problem 2 not be seen by the human eye? What kind of device is necessary to detect electron waves? 4. What is the energy of a light quantum (photon) which has a wavelength of 600 nm? Compare the energy with the electron wave energy calculated in Problem 2 and discuss the difference. with a valncitv of 200 km/h. What is the
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