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Question: priority encoder 8 to 3 boolean algebra can someone explain...

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Priority Encoder 8 to 3 (Boolean Algebra)

Can someone explain to me for output Q2, how the Boolean equation for Q2 reduces/simplifies to just Q2 = D4 + D5 + D6 + D7?

What boolean laws or reduction steps are being performed on this minterm expression?

Binary Digital Inputs 0 0 0 00 0 0 10 0 0

Output Q2 Q2_Σ(4, 5, 6, 7)

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