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Question: problem 1 15 points arocket i lunched vertically from point...

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Problem 1, 15 points Arocket i lunched vertically from point Po(0), with the rocket motor providing thrust equivalent to an acceleration of 19.8 m/s2. After 3 seconds, the rocket reaches point P, and the rocket motor shuts down. For I second (up to a total flight time of 4 seconds), the rocket flies without thrust, while it rotates by 45o. Then, at point P2 the rocket motor is restarted, again providing thrust equivalent to an acceleration of 19.8 m/s? in direction of its new heading for 2 seconds (up to a total of flight time of 6 seconds). After that, the rocket will fly without thrust. Find the maximum height of the flight path, and the horizontal distance of the point where the maximum height is reached from the launch point (i.e. the coordinates of Ps), as well as the coordinates of Ps, P2 and Ps 9 12 - maximum height 12 - rocket motor stops again P, (, 4s)-rocket motor restarts P, (t1 39-rocket motor stops White arrow: direction of thrust acceleration from rocket motor P 0)-launch Gravitational acclentionisg (98) m/s? , drag from air resistance is ignored. In each step, calculating one digit right of the decimal point is sufficient.
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