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  3. problem 6 explain what is wrong in the following proof...

Question: problem 6 explain what is wrong in the following proof...

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Problem 6. Explain what is wrong in the following proof and write a correct version of it For any real number b such that 1 b< 5, prove that b -6 5b< 0 Proof Suppose that l 〈 b 〈 5. b3-6b2 + 5b = b(b2-6b+ 5) 〈 0 so, since b > 0 we have b2ー6b+ 5 〈 0. But we notice that 62- 6b+5 (b-1) (b-5). Since 1< b<5, we know that b-1 0 and b 5 <0 so indeed

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