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- student id 23245172 1 given the subnet mask of 2552552400...
Question: student id 23245172 1 given the subnet mask of 2552552400...
Question details
Student Id 23245172
1. Given the subnet mask of 255.255.240.0 and the broadcast address 140.20Y.1X1.255, find the network address. Here X is the first digit of your student ID and Y is the last digit of your student ID.
Solution by an expert tutor
