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Question: the 227000lb spaceshuttle orbiter touches down at about 239 mihr...

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The 227000-lb space-shuttle orbiter touches down at about 239 mi/hr. At 203 mi/hr its drag parachute deploys. At 43 mi/hr, the chute is jettisoned from the orbiter. If the deceleration in feet per second squared during the time that the chute is deployed is -o.00015v2 (speed v in feet per second), determine the corresponding distance s traveled by the orbiter. Assume no braking from its wheel brakes Answer: S ft the tolerance is +/-2%

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