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Question: the answer is the following...

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The system shown in Figure A16 has an output of 0.8 p.u. active power and 0.2 p.u. reactive power at bus 2 and a reactive power output of 0.4 p.u. at bus 3 (100 MVA base). Bus 1 is the swing bus with a voltage of 1 p.u. Yo =-15 p.u. Y13--j3p.u. Y23--j4p.u Figure A16 Use the admittance matrix and the Gauss-Seidel method to solve for the voltages at buses 2 and 3 (show just one iteration).

The answer is the following

V2 0.9822-5.194°p.u V 0.9322-3.126°pau.

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