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Question: the answer of number 2 is e418 106 ev and...

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2. What should be the energy of an electron so that the associated electron waves have a wavelength of 600 nm? ince the visible region spans between approximately 400 nm and 700 nm, why can the electron wave mentioned in Problem 2 not be seen by the human eye? What kind of device is necessary to detect electron waves? 4. What is the energy of a light quantum (photon) which has a wavelength of 600 nm? Compare the energy with the electron wave energy calculated in Problem 2 and discuss the difference. le uith a velocity of 200 km/h. What is the
The answer of number 2 is E=4.18 *10^-6 ev
And number 4 is E=2.07 ev
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