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Question: the catalytic oxidation of ethanol over tantalum oxide can be...

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The catalytic oxidation of ethanol over tantalum oxide can be described by the overall reaction:

CHSOH(g) O2 (g) CH3CHO +H20(g) This reaction is believed to proceed by a mechanism in which ethanol is adsorbed on one type of site, S, and oxygen is absorbed on a different type of site, S. Ethanol undergoes dissociative adsorption on sites of type S as: Step 1: C2H5OH(g) 2 S S C2H5O-S H-S with forward and reverse rate constants ki and k.I, respectively. Oxygen also undergoes dissociative adsorption on two sites of type S (presumably metal ions as: Step 2: o20g) 2 S S 2 O-S with forward and reverse rate constants k2 and k.2, respectively. A surface reaction follows: Step 3: C2H5O-S O-S CH3CHO(g) HO-S S with rate constant K3. The absorbed hydroxyl radical is converted into water by the last step: Step 4: HO-S H-S H200g) S S with forward and reverse rate constants ks and k 4, respectively. If the surface reaction (Step 3) is rate limiting, show that the rate law is: Ko, and the rate constant k depends on ka, K Ko the C2H5OH where K k C HSOH total concentration of sites of type S, and the total concentration of sites of type S Assume that the concentrations of absorbed atomic hydrogen and ethanolate are identical (i.e., H-s] C2HSO SD and that the concentration of adsorbed hydroxide is negligible (i.e., Ho 0)

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