# Question: the clausiusclapeyron equation is mm2m1 where hm is the molar...

###### Question details

The Clausius-Clapeyron equation is

𝑑𝑃/𝑑𝑇=𝐻m/(𝑇(𝑉m2−𝑉m1))

where *H*_{m} is the molar enthalpy change from
phase 1 to phase 2 and all other symbols have their usual meanings.
The equations of the sublimation and vaporization curves for a
particular substance are given by:

ln*P* = 19–
(15900/ *T*) sublimation

ln*P* = 21–
(15300/ *T*) vaporization

a) Find the temperature and pressure of the triple point for this substance.

b) Assuming the molar volume in the vapour phase is much larger than the molar volume in both the liquid and solid phases, and that the gaseous phase behaves as an ideal gas, calculate the molar enthalpy changes of vaporization and sublimation for this substance.