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Question: the differences in electric potential or voltage we use both...

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The differences in electric potential or voltage (we use both terms interchangeably) can be used to determine changes in the electric potential energy of a charged object. If I have a particle with a charge q that is moving between two points in space which have a difference in electric potential (or voltage) of ΔV, the change in electric potential energy of that object is given by ΔEPE = q ΔV. When answering the following questions remember that a gain in electric potential energy is given by ΔEPE > 0 and a loss of electric potential energy is given by ΔEPE < 0.

Suppose a particle with a charge of +2.40 nC moves from a point where the electric potential is 24.0 V to a point where the electric potential is 79.0 V. What is the change in electric potential energy?

Suppose a particle with double that charge, +4.80 nC (nanocoulombs) moves from a point where the electric potential is 24.0 V to a point where the electric potential is 79.0 V. What is the change in electric potential energy?

Suppose a particle with a charge of +2.40 nC moves from a point where the electric potential is 79.0 V to a point where the electric potential is 24.0 V. What is the change in electric potential energy?

Suppose a particle with a charge of -2.40 nC moves from a point where the electric potential is 24.0 V to a point where the electric potential is 79.0 V. What is the change in electric potential energy?

Lastly, suppose a particle with a charge of +2.40 nC is released from rest at a point where the electric potential is 79.0 V. Just like a block sliding down a ramp as it loses potential energy, it will gain kinetic energy. What is the kinetic energy of the particle when it has reached a point in space where the electric potential is 24.0 V?

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