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the equilibrium constant for the dissociation of iodine molecules to...

Question: the equilibrium constant for the dissociation of iodine molecules to...

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The equilibrium constant for the dissociation of iodine molecules to iodine atoms 12 (g) 근 2 1(g) is 3.76 >< 10-3 at 1000 K. Suppose 0.245 mol of12 is placed in a 18.0 L flask at 1000 K. What are the concentrations of 12 and I when the system comes to equilibrium? [12) LI

You place 1.16 mol of pure SOs in an 8.0-L flask at 1300 K. At equilibrium, 0.45 mol of O2 has been formed. Calculate Ke for the reaction at 1300 K. 2 SOs (g) 2 SO2 (8) + 02(g)

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