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Question: the location is located in coogee oval at 3355098quots 15115209quote...

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The location is located in Coogee oval at 33°55'09.8"S 151°15'20.9"E. The length of the sides are 30.40m, 29.45m, 33.10m, 24.66m and the total area is 849.19m^2. The diagonal line across 50.00m.
 
To calculate the area we can divide this into 2 triangles. To find the length of the diagonal component d we use the law of cosines so d^2 = 2.47^2+3.31^2-2*2.47*3.31*cos(99.74) = 5.56 and so d = 2.36. Now we have two triangles one with side lengths 2.47, 3.31, 2.36 and one with side lengths 3.03, 2.95, 2.36. Now we can use Heron's formula to find the area of these two triangles. The perimeter of the first triangle is (2.47+3.31+2.36)/2 = 4.07 and so by Heron's formula we have the area of the first triangle = √4.07*(4.07-2.47)*(4.07-3.31)*(4.07-2.36) = 2.91. The perimeter of the ssecond triangle is (3.03+2.95+2.36)/2 = 4.17 and so the area of the second triangle = √4.17*(4.17-3.03)*(4.17-2.95)*(4.17-2.36) = 3.24. So we add the two areas to get total area of 3.27+2.91 = 6.18. Now this is not to scale we have to multiply it by 100 to get it to the correct scale, so using our calculations get the total area to be 618m^2. Which is not close to the original estimate by google, there is possibly a mistake in the calculations.

 

PLEASE THIS SOLUTION OF PART A REGARDING A I NEED TO FOLLOW B AND C PLEASE HELP ME IMMEDIATELY 

 

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