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  3. typically solving for y is quite difficult however...

Question: typically solving for y is quite difficult however...

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Typically, solving for μ , y is quite difficult. However, special cases occur when μ is a function either just z, or just y and not both. of (a) Suppose μ(x) (no y dependence). Show that the condition for exactness then results in dr (b) Derive the similar formula for when μ-μ(y) (no x dependence). (c) Find an integrating factor for the equation (3ry + уг) + (x2 +xy)2/-0 and use it to solve the equation

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