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Question: when looking at the figure i understand how you can...

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figure 7 mg sin θ ng cose mg[Q7-Home]: Show that the algebraic solution for Al-tan ф) is exactly the same even when choosing a different set of axes i.e.

When looking at the Figure I understand how you can derive the tan when the axis is placed on top of the forces (X mgsin) however this asks you to derive it if you were to set the axis parallel to the ground. This makes the accelerations a vector in the plane rather than the axis themselves. I was hoping to find a more in-depth and derive solution to this problem

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